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30t^2-t=1
We move all terms to the left:
30t^2-t-(1)=0
We add all the numbers together, and all the variables
30t^2-1t-1=0
a = 30; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·30·(-1)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*30}=\frac{-10}{60} =-1/6 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*30}=\frac{12}{60} =1/5 $
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